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Frontier Sciences
Fusion Science
1955
Research

Lawson Criterion (Fusion)

nTτ>3×1021 keV⋅s/m3n T \tau > 3 \times 10^{21} \text{ keV·s/m}^3

Fusion breakeven requires sufficient plasma density, temperature, and confinement time triple product.

By John Lawson

Frontier Sciences
Lawson Criterion (Fusion)
1955 · John Lawson
Why it matters: Set the target for ITER, NIF, and commercial fusion ventures.

Discoverers: John Lawson (1955)

What does it mean?

Fusion breakeven requires sufficient plasma density, temperature, and confinement time triple product.

Why should I care?

Set the target for ITER, NIF, and commercial fusion ventures.

Variables & Units

SymbolNameUnitMeaning
nnDensitym⁻³Plasma ion density
TTTemperaturekeVPlasma temperature
ττConfinement timesEnergy confinement

Worked Example

NIF 2022 achieved ignition; ITER targets Q>10.

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Lawson Criterion (Fusion)

nTτ>3×1021 keV⋅s/m3n T \tau > 3 \times 10^{21} \text{ keV·s/m}^3

Real-world impact

Space systems

Orbital mechanics enables global connectivity and exploration.

Photo: Unsplash — rocket launch

Fusion breakeven requires sufficient plasma density, temperature, and confinement time triple product.

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